Warriors forward David Lee has been named the NBA Western Conference Player of the Week for games played Monday, December 10, through Sunday, December 16, the NBA announced today.
In four games last week, Lee averaged 22.8 points, 12.5 rebounds, 2.8 assists and 1.00 steal, while shooting 60.6% (40-66 FG) from the field, leading the Warriors to a 3-1 record to help complete a season-long, seven-game road trip with a franchise record 6-1 mark.
The 6-9 forward registered at least 20 points and 10 rebounds in all four games, as he did in all seven games of the road trip.
Lee is the first NBA player to post such numbers since 1972 when Kareem Abdul-Jabbar did so in each of a nine-game road trip.
The award is the second such honor in Lee’s career, previously earning the Eastern Conference accolade on February 1, 2009, as a member of the New York Knicks. It is the 29th time a Warriors player has been named Player of the Week since the NBA began giving out the award in 1979 and the first since Monta Ellis on March 12, 2012.
In 24 games this season, the seven-year veteran is averaging 19.2 points (13th in NBA), 11.5 rebounds (5th), 3.4 assists and 1.00 steal, while shooting 52.3% from the field (19th). He also ranks second in the league in double-doubles (16) and has posted ten 20-point/10-rebound games, matching LeBron James for most in the NBA this season.
Lee is currently the only player in the NBA averaging at least 19 points, 11 rebounds and three assists, something only Wilt Chamberlain, Nate Thurmond, Neil Johnston and Jerry Lucas have done in franchise history.
Indiana’s Paul George earned Player of the Week honors in the Eastern Conference.
--Golden State Warriors media services